0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.
The number of moles of a substance can be calculated using the following expression:
PV = nRT
Where;
0.75 × 11.2 = n × 0.0821 × 300
8.4 = 24.63n
n = 8.4 ÷ 24.63
n = 0.34 moles
Therefore, 0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.
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