The given dimensions of 9.5, 6, 7, and 6.5 cm gives the following
perimeter and area of the trapezium.
How can the area and perimeter of the trapezium be found?
The perimeter of a trapezoid is given as follows;
Perimeter = The sum of the lengths of the sides
Which gives;
Perimeter = 6 + 7 + 6.5 + 9.5 = 29
The perimeter of the trapezoid = 29 cm
The area of the trapezoid is given as follows;
[tex]Area = \mathbf{ \dfrac{Sum \ of \ the \ parallel \ sides }{2} \times Height}[/tex]
Which gives;
[tex]Area = \dfrac{7 + 9.5 }{2} \times 6 = 49.5[/tex]
The area of the trapezoid = 49.5 cm²
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