valereigh05
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SORRY BUT I HAVE ANOTHER PROBLEM!!!!! WILL GIVE BRAINLIEST & 50 POINTS

For all [tex]x \neq -3, \frac{x^2-6x +9}{6x-18} =[/tex]

F. [tex]\frac{x+3}{x-3}[/tex]

G. [tex]\frac{x-3}{6}[/tex]

H. [tex]\frac{1}{x-3}[/tex]

J. [tex]x-3[/tex]

K. [tex]\frac{x}{3}[/tex]

Respuesta :

Emily216454865

Answer:

The correct option is G.Hope this help!!

Ver imagen Emily216454865

Just factor out

[tex]\\ \rm\hookrightarrow \dfrac{x^2-6x+9}{6x-18}[/tex]

[tex]\\ \rm\hookrightarrow \dfrac{x^2-3x-3x+9}{6(x-3)}[/tex]

[tex]\\ \rm\hookrightarrow \dfrac{x(x-3)-3(x-3)}{6(x-3)}[/tex]

[tex]\\ \rm\hookrightarrow \dfrac{(x-3)(x-3)}{6(x-3)}[/tex]

[tex]\\ \rm\hookrightarrow \dfrac{x-3}{6}[/tex]

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