The probability that Maria succeeds at any given free-throw is 75%. She was curious how many free-throws she can expect to succeed in a sample of 10 free-throws. She simulated 25 samples of 10 free-throws where each free-throw had a 0.75 probability of being a success. Maria counted how many free-throws were successes in each simulated sample. Here are her results:​

Respuesta :

Answer:

5: 0 successes

6: 5 successes

7: 8 successes

8: 6 successes

9: 6 successes

10: 1 success

We need to use her results to estimate the probability that she succeeds at fewer than 7 free-throws in a sample of 10 free-throws.

First, find out how many successes were less than 7 (out of 25), which is 5.

now, we divide 5 by 25 (5/25, formula being number/total attempts) and simplify into a decimal, which comes out to 0.2

Probability w/ Venn Diagrams

Step-by-step explanation:

Disclaimer: The question was incomplete. The complete question can be seen in the image attached.

The estimated probability of Maria succeeding at fewer than 7 free throws in a sample of 10 free throws is 1/5 or 0.2.

What is the probability of an event?

The probability of an event is the fractional value showing how likely is that event to occur. It is determined by the formula =

The number of outcomes favorable to the event/the total number of outcomes.

How do we solve the given question?

The results from the 25 samples showing the number of success in each trial of 10 throws are:

5 success: 0 outcomes

6 success: 5 outcomes

7 success: 8 outcomes

8 success: 6 outcomes

9 success: 5 outcomes

10 success: 1 outcome.

We are asked to estimate the probability that Maria succeeds at fewer than 7 throws in a sample of 10 free throws.

From the result of 25 samples of 10 free throws each, we see that Maria succeeds fewer than 7 times, that is, 5 and 6 times for 0 + 5 = 5 outcomes.

∴ The probability of Maria succeeding at fewer than 7 throws in a sample of 10 free throws = 5/25 (favorable outcomes/total outcomes)

= 1/5 or 0.2.

So, the estimated probability of Maria succeeding at fewer than 7 free throws in a sample of 10 free throws is 1/5 or 0.2.

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