Answer:
Option D
Step-by-step explanation:
Hello!
Recall the quadratic equation: [tex]x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}[/tex]
Remember that a quadratic equation is written in the form [tex]ax^2 + bx + c\\[/tex]
So:
Plug the values in and solve:
[tex]x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}\\\\x = \frac{-5\pm\sqrt{5^2 - 4(2)(-1)}}{2(2)}$\\\\x = $\frac{-5\pm\sqrt{25 +8}}{2(2)}$\\\\x = $\frac{-5\pm\sqrt{33}}{4}[/tex]
This would be [tex]\boxed{\text{Option D}}[/tex]
