elizabethpenaa301
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61.2 grams of hydrogen sulfide react with 64.0 grams of Sulfur dioxide and produce 62.2 grams of solid sulfur (S8). (a) What amount of solid sulfur do you expect to be produced, theoretically, by the reaction with the given quantities of reactants? (Limiting reagent problem

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indrawboy

Reaction

8SO₂ + 16H₂S → 3S₈ + 16H₂O

find limiting reactant

mol SO₂ = 64 : 64 g/mol =  1

mol H₂S = 61.2 : 34 g/mol = 1.8

ratio mol:coefficient

SO₂= 1 : 8= 0.125

H₂S=1.8 : 16 = 0.113

H₂S as a limiting reactant (smaller ratio)

mol S₈ will be based on limiting reactant (H₂S)

mol S₈ = 3/16 x 1.8 = 0.3375

mass S₈ = 0.3375 x 256 = 86.4 g

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