Find the length of the second leg of the triangle round to the nearest hundredth

Answer:
[tex]\displaystyle \frac{3\sqrt{230}}{5}[/tex]
Step-by-step explanation:
Use the Pythagorean Theorem:
[tex]\displaystyle a^2 + b^2 = c^2 \\ \\ 9,7^2 + b^2 = 13,3^2; \sqrt{82,8} = \sqrt{b^2} \\ \\ \frac{3\sqrt{230}}{5}\:[or\:9,0994505329...] = b[/tex]
So, you have this:
[tex]\displaystyle 9,1 ≈ b[/tex]
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