The first four-term of the sequence is found by the given equation [tex]a_{n-1} = 4a_n[/tex] is given as 144, 36, 9, and 9/4.
A sequence is a list of elements that have been ordered in a sequential manner, such that members come either before or after.
The given equation will be
[tex]\rm a_n = \dfrac{a_{n-1}}{4} \\\\a_{n-1} = 4a_n[/tex]
And
[tex]a_4 = 2 \dfrac{1}{4} = \dfrac{9}{4}[/tex]
For n = 4, we have
[tex]\rm a_{4-1} = 4a_4\\\\a_3 \ \ \ = 4*\dfrac{9}{4} \\\\ a_3 \ \ \ = 9[/tex]
For n = 3, we have
[tex]\rm a_{3-1} = 4a_3\\\\a_2 \ \ \ = 4*9 \\\\ a_2 \ \ \ = 36[/tex]
For n = 2, we have
[tex]\rm a_{2-1} = 4a_2\\\\a_1 \ \ \ = 4*36 \\\\ a_1 \ \ \ = 144[/tex]
More about the sequence link is given below.
https://brainly.com/question/21961097
