okrj
contestada

Find an equation for the perpendicular bisector of the line segment whose endpoints are (5, 5) and ( 7, 1).​

Respuesta :

Answer:

  x -2y = 0

Step-by-step explanation:

A perpendicular bisector is a line perpendicular to a given line or segment that goes through the midpoint between given points. The perpendicular line will have a slope that is the opposite reciprocal of the slope of the segment between the given points.

__

The midpoint between A and B is ...

  M = (A +B)/2

  M = ((5, 5) +(7, 1))/2 = (12, 6)/2 = (6, 3)

The slope of the line between A and B is ...

  m = (y2 -y1)/(x2 -x1)

  m = (1 -5)/(7 -5) = -4/2 = -2

__

The opposite reciprocal of the slope of the given segment is ...

  m' = -1/-2 = 1/2

The point-slope form of the equation of the perpendicular bisector can be written as ...

  y -k = m(x -h) . . . . . . line with slope m through point (h, k)

  y -3 = 1/2(x -6) . . . . line with slope 1/2 through point (6, 3)

Multiplying by 2 gives ...

  2y -6 = x -6

Subtracting (2y -6) gives the standard-form equation ...

  x -2y = 0

Ver imagen sqdancefan