Respuesta :
Answer:
(f o g)(x)= 3x + 14
(g o f)(x) = 3x + 4
Step-by-step explanation:
(f o g)(x) = f(g(x)) = f(x + 5) = 3(x + 5) - 1 = 3x + 15 - 1 = 3x + 14
(g o f)(x) = g(f(x)) = g(3x - 1) = 3x - 1 + 5 = 3x + 4
Answer:
[tex](f \circ g)(x) = 3x + 14[/tex]
[tex](g \circ f)(x) = 3x + 4[/tex]
Step-by-step explanation:
Hello!
Rewrite the equations:
- [tex](f \circ g)(x) = f(g(x))[/tex]
- [tex](g \circ f)(x) = g(f(x))[/tex]
Given that:
- f(x) = 3x - 1
- g(x) = x + 5
Solve for [tex](f \circ g)(x)[/tex]:
- [tex]f(g(x)) = 3(g(x)) - 1[/tex]
- [tex]f(x + 5) = 3(x + 5) - 1[/tex]
- [tex]f(x + 5) = 3x + 15 - 1[/tex]
- [tex]f(x + 5) = 3x + 14[/tex]
[tex](f \circ g)(x) = 3x + 14[/tex]
Solve for [tex](g \circ f)(x)[/tex]:
- [tex]g(f(x)) = f(x) + 5[/tex]
- [tex]g(3x - 1) = (3x - 1) + 5[/tex]
- [tex]g(3x - 1) = 3x +4[/tex]
[tex](g \circ f)(x) = 3x + 4[/tex]