okrj
contestada

Find an equation for the perpendicular bisector of the line segment whose endpoints are (6,9) and (2,5).​

Respuesta :

Answer:

  x + y = 11

Step-by-step explanation:

The perpendicular bisector goes through the midpoint of the segment and has a slope that is the opposite reciprocal of the slope of the segment. The midpoint is ...

  M = (A+B)/2 = ((6, 9) +(2, 5))/2 = (6+2, 9+5)/2 = (8, 14)/2

  M = (4, 7) = (Mx, My)

The slope can be found from the differences of the coordinates of the two points:

  (Δx, Δy) = (2 -6, 5 -9) = (-4, -4)

Factoring out -4, this becomes

  (Δx, Δy) = (1, 1)

__

These values can be used directly to form the equation of the perpendicular line:

  (Δx)(x -Mx) +(Δy)(y -My) = 0

  1(x -4) +1(y -7) = 0

  x + y = 11 . . . . . . . . . add 11 and simplify

___

Additional comment

Using "standard form" for the equation, we don't actually need the value of the slope. If you were to use point-slope form or slope-intercept form for the equation of the line, then you would need to know the slope of the segment is ...

  m = Δy/Δx = 1/1 = 1

and the slope of the perpendicular is ...

  m' = -1/m = -1/1 = -1

_____

To read more about perpendicular bisectors, see ...

https://brainly.com/question/26903617

Ver imagen sqdancefan