[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]
The Length of PQ such that Triangle JKL is similar to Triangle PQR ~
To make the given triangles similar, we have to get the ratios of each of their corresponding side to be equal to one another.
That is :
[tex]\qquad \sf \dashrightarrow \: \dfrac{PQ}{12} = \dfrac{9}{6} [/tex]
[tex]\qquad \sf \dashrightarrow \: PQ = \dfrac{9}{6} \times 12[/tex]
[tex]\qquad \sf \dashrightarrow \: PQ = {9}{} \times 2[/tex]
[tex]\qquad \sf \dashrightarrow \: PQ = 18 \: units[/tex]
hence, the option C is correct
