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Consider the following reaction: NO2(g)→NO(g)+12O2(g) The following data were collected for the concentration of NO2 as a function of time:
Time (s) [NO2] (M) 0 1.000 10 0.951 20 0.904 30 0.860 40 0.818 50 0.778 60 0.740 70 0.704 80 0.670 90 0.637 100 0.606
A. What is the average rate of the reaction between 10 and 20 s?
B. What is the average rate of the reaction between 50 and 60 s?
C. What is the rate of formation of O2 between 50 and 60 s?

Respuesta :

marianaegarciaperedo

The term rate of reaction, RR, refers to the speed at which the reactants of a chemical reaction are turned into products. A) RR = 0.0047 M/s; B) RR = 0.0038 M/s; C) 0.0019 M/s.

What is the rate of reaction?

When talking about the rate of reaction we refer to the speed at which a chemical reaction occurs, turning reactants into products.

It can be measured as

  • the concentration of reactant consumed in a certain time
  • the concentration of product formed during the same time.

The formula to calculate the rate of reaction is the following,

RR = Δ concentration / Δ Time

Where,

  • RR is the rate of reaction
  • Δ concentration is the change of concentration, C2 - C1 or C1 - C2
  • Δ Time is the change in time, T2 - T1

In the exposed example, the chemical reaction is

                                       

                              NO₂(g) → NO(g) + 12 O₂(g)

So the rate of reaction can be measured according to

  • how fast NO₂ is consumed, or
  • how fast NO and O₂ are produced.

Since the collected data was the concentration of NO₂ as a function of time, then the rate of reaction was measured as the speed at which NO₂ was consumed.

A. What is the average rate of the reaction between 10 and 20 s?

Available data

  • C1 = 0.951 M
  • C2 = 0.904 M
  • T1 = 10 s
  • T2 = 20 s

RR = Δ concentration / Δ Time

RR = (0.951 - 0.904) / 20 - 10

RR = 0.074 / 10

RR = 0.0047 M/s

B. What is the average rate of the reaction between 50 and 60 s?

Available data

  • C1 = 0.778 M
  • C2 = 0.740 M
  • T1 = 50 s
  • T2 = 60 s

RR = Δ concentration / Δ Time

RR = (0.778 - 0.740) / 60 - 50

RR = 0.038 / 10

RR = 0.0038 M/s

C. What is the rate of formation of O₂ between 50 and 60 s?

Now, since NO₂ turns into NO and O₂, then

                  RR = Rate of NO₂ consumed = 2x rate of O₂ produced

If RR between 50 and 60 s is 0.0038 M/s, then the rate of formation of O₂ is,

Rate of NO₂ consumed / 2 =  rate of O₂ produced

0.0038 M/s / 2 = rate of O₂ produced

0.0019 M/s = rate of O₂ produced

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