Answer:
[tex]\boxed{a=2,\:b=4}[/tex]
Step-by-step explanation:
[tex]\begin{bmatrix}3a+5b=26\\ a+5b=22\end{bmatrix}[/tex]
Isolate a from 3a + 5b = 26,
[tex]a=\cfrac{26-5b}{3}[/tex]
[tex]\begin{bmatrix}\cfrac{26-5b}{3}+5b=22\end{bmatrix}[/tex]
[tex]\begin{bmatrix}\cfrac{26+10b}{3}=22\end{bmatrix}[/tex]
Now, Isolate b for
[tex]\cfrac{26+10b}{3}=22\:\:\boxed{b=4}[/tex]
Now, Substitute b=4
[tex]a=\cfrac{26-5\times \:4}{3}[/tex]
[tex]\cfrac{26-5\times \:4}{3}\:\:\boxed{a=2}[/tex]
[tex]\boxed{a=2,\:b=4}[/tex]
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