6.07 grams is the theoretical yield of calcium phosphate (Ca₃(PO₄)₂).
Mass of any substance can be calculated by using moles as:
n = W/M, where
W = required mass
M= molar mass
Given chemical reaction is:
3Ca(NO₃)₂ + 2Na₃PO₄ → 6NaNO₃ + Ca₃(PO₄)₂
From the stoichiometry it is clear that:
3 moles of Ca(NO₃)₂ = produce 1 mole of Ca₃(PO₄)₂
Given mass of Ca(NO₃)₂ = 96.1g
Mole of Ca(NO₃)₂ = 96.1g/164g/mol = 0.5859moles
So, 0.5859 moles of Ca(NO₃)₂ = produce 0.5859×1/3 = 0.0196 moles of Ca₃(PO₄)₂
Required mass of Ca₃(PO₄)₂ will be calculated by using moles as:
W = 0.0196mole × 310g/mole = 6.07 grams
Hence, 6.07 grams is the theoretical yield of calcium phosphate.
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https://brainly.com/question/15373263
