18.14% of the bags contains less than 22 kg
Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:
z = (raw score - mean) / standard deviation
Given that:
Mean = 22.73 kg, standard deviation = 0.80 kg
a) For <22:
z = (22 - 22.73)/0.8 = -0.91
P(z < -0.91) = 0.1814
18.14% of the bags contains less than 22 kg
Find out more on z score at: https://brainly.com/question/25638875