In filling bags of nitrogen fertilizer, it is desired to hold the average overfill to as low a value as possible. The lower specification limit is 22.00 kg (48.50 lb), the popu-lation mean weight of the bags is 22.73 kg (50.11 lb), and the population standard deviation is 0.80 kg (1.76 lb). What percentage of the bags contains less than 22 kg? If it is permissible for 5% of the bags to be below 22 kg, what would be the average weight? Assume a normal distribution.

Respuesta :

18.14% of the bags contains less than 22 kg

What is z score?

Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z = (raw score - mean) / standard deviation

Given that:

Mean = 22.73 kg, standard deviation = 0.80 kg

a) For <22:

z = (22 - 22.73)/0.8 = -0.91

P(z < -0.91) = 0.1814

18.14% of the bags contains less than 22 kg

Find out more on z score at: https://brainly.com/question/25638875