A beam of length 10m can support a weight of 62kg.
It is given that
Weight W ∝ 1/ Length L
W ∝ 1/L
W = k/L...........eq1
where k is constant of proportionality
The constant of proportionality is the ratio that relates two given values.
It is given that when L= 2m, W = 310kg
310 = k/2
k = 620
So put the k value in eq1,
eq1 becomes,
W = 620/L
when L = 10
W = 620/10
W =62kg
Therefore, a beam of length 10m can support a weight of 62kg.
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