The weight that a horizontal beam can support varies inversely as the length of the beam. Suppose that a 2-m beam can support 310 kg. How many kilograms can a 10-m beam support? a. 0. 0161 kg b. 62 kg c. 15. 5 kg d. 0. 0645 kg.

Respuesta :

A beam of length 10m can support a weight of 62kg.

It is given that

Weight W ∝ 1/ Length L

W ∝ 1/L

W = k/L...........eq1

where k is constant of proportionality

What is the constant of proportionality?

The constant of proportionality is the ratio that relates two given values.

It is given that when L= 2m, W = 310kg

310 = k/2

k = 620

So put the k value in eq1,

eq1 becomes,

W = 620/L

when L = 10

W = 620/10

W =62kg

Therefore, a beam of length 10m can support a weight of 62kg.

To get more about the constant of proportionality visit:

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