Equations 1 and 4 would produce a parabola as they follow the general equation of a parabola.
Given equations are:
[tex]1)-5x^2+4x-7y+14 = 0\\\\2)-x^2 + 6x +y^2-8=0\\\\3)9x^2-12xy+4y^2+4x-y+5=0\\\\4)12x+6y-5y^2+14=0[/tex]
The general equation of a parabola
[tex]y = a(x^2+h^2-2xh)+k\\[/tex] or [tex]x= a(y^2+k^2-2yk)+h[/tex]
where h and k are vertices of the parabola.
Each equation follows the same pattern as the general equation of a parabola except the second and third equation
Therefore, equations 1 and 4 would produce a parabola as they follow the general equation of a parabola.
To get more about parabola visit:
https://brainly.com/question/4148030
Answer:
A. –5x2 + 4x – 7y + 14 = 0
C. 9x2 – 12xy + 4y2 + 4x – y + 5 = 0
D. 12x + 6y – 5y2 + 14 = 0
I got it right on edge trust me
