A 25 kg sled is pulled across a horizontal surface by a 200 N force at a constant velocity. What is the coefficient of friction between the sled and the surface?

Respuesta :

Answer:

0.82

Explanation:

constant velocity.means acceleration a = 0, so net force = 0

F - μmg = ma = 0

so μ = F/(mg) = 200/(25*9.8) = 0.82