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In the previous question, you used the Hardy-Weinberg equation to determine the frequencies of the genotypes for HH, Hh, and hh, given gene frequencies of H = 0. 2 and h = 0. 8. These frequencies were: HH = 0. 04 Hh = 0. 32 hh = 0. 64 Now, determine the expected numbers of each organism in the population (total size = 150): Number of HH = Number of Hh = Number of hh =.

Respuesta :

The expected number of each organism in the population is HH = 60, Hh = 48, hh = 96.

What is the Hardy-Weinberg equation?

The hardy-Weinberg equation is a mathematical equation used to calculate the genetic variation of a population at equilibrium.

The given frequencies are HH = 0.04

Hh = 0.32

hh =  0.64

So, the percentages are HH = 4%, Hh = 32%, hh = 64%.

The total percentage will be (4 + 32 + 64 = 100)

The total size is 150

Now,

The number of HH genotype is 0.4 × 150 = 60

The number of Hh genotype is 0.32 × 150 = 48

The number of hh genotype is 0.64 × 150 = 96

The total is 6 + 48 + 96 = 150

Thus, the expected number of each organism in the population is HH = 60, Hh = 48, hh = 96.

Learn more about  Hardy-Weinberg equation

https://brainly.com/question/5028378

Answer:

HH= 6

Hh= 48

hh=96

The next answer is NO

Explanation:

I did it

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