Janae and Jerome each have m marbles. Gwen has 4(m 2) marbles. John has 8m 4 marbles. If John has more marbles than Janae, Jerome, and Gwen combined, how many marbles might Janae and Jerome each have? Select each possible answer.

Respuesta :

Janae and Jerome each have either 3, or 4 or 5 marbles. Option C, D and E are correct.

How do you calculate the value of integer m?

Given that the number of marbles has:

Janae = m

Jerome  = m

Gwen = 4(m+2)

John = 8m+4

John has more marbles than Janae, Jerome, and Gwen combined, So this can be written as,

[tex]8m+4 \geq m + m + 4(m+2)[/tex]

[tex]8m+4\geq 2m + 4m+8[/tex]

[tex]8m+4 \geq 6m+8[/tex]

[tex]2m\geq 4[/tex]

[tex]m\geq 2[/tex]

It means that the value of m is greater than 2, it can be 3, 4 or 5.

Hence we can conclude that Janae and Jerome each have either 3, or 4 or 5 marbles. Options C, D and E are correct.

To know more about integers, follow the link given below.

https://brainly.com/question/1768255.