Answer:
Step-by-step explanation:
3y - 2x +2 = 0
3y = 2x - 2
[tex]y = \dfrac{2}{3}x-\dfrac{2}{3}[/tex]
y = mx + b
Slope of line a = 2/3
Product of slope of perpendicular line = -1
[tex]Slope \ of \ line \ b = \dfrac{-1}{\dfrac{2}{3}}=\dfrac{-3}{2}[/tex]
Equation of line b:
[tex]y=\dfrac{-3}{2}x+b[/tex]
Line b passes through (4,7)
[tex]7 = \dfrac{-3}{2}*4+b\\\\\\7= -6 + b\\\\b = 7 + 6\\\\b = 13[/tex]
Equation of line b:
[tex]y=\dfrac{-3}{2}x+13[/tex]
Multiply the equation by 2
2y = -3x + 26
3x + 2y - 26 = 0
