The chemical equation below shows the combustion of propane (C3H8). C3H8 5O2 Right arrow. 3CO2 4H2O The molar mass of oxygen gas (O2) is 32. 00 g/mol. The molar mass of C3H8 is 44. 1 g/mol. What mass of O2, in grams, is required to completely react with 0. 025 g C3H8? 0. 018 grams 0. 034 grams 0. 045 grams 0. 091 grams.

Respuesta :

Molar mass is the ratio of the mass to that of the moles of the substance present in the compound. The mass of the oxygen required for the complete combustion is 0.091 gm.

What is mass?

Mass is the quantity or the weight of the substance occupied in the reaction and is the product of the molar mass and the moles of the substance.

The reaction for the combustion of propane can be shown as:

[tex]\rm C_{3}H_{8} + 5O_{2} \rightarrow 3CO_{2} + 4H_{2}O[/tex]

Moles of propane can be calculated as:

[tex]\begin{aligned}\rm moles &=\rm \dfrac{mass}{molar\; mass}\\\\&= \dfrac{0.025}{44.1}\\\\&= 5.66\times 10^{-4}\end{aligned}[/tex]

The ratio of the number of moles of propane and oxygen is 1:5. So the moles of oxygen will be [tex]2.83 \times 10^{-3}\;\rm mol[/tex].

Mass of oxygen can be calculated as:

[tex]\begin{aligned}\rm mass &= \rm molar\;mass \times mass\\\\&= 2.83 \times 10^{-3}\;\rm mol \times 32 \;\rm g/mol\\\\&= 0.091\;\rm gm\end{aligned}[/tex]

Therefore, option D. 0.091 gm is the mass of oxygen.

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