Molar mass is the ratio of the mass to that of the moles of the substance present in the compound. The mass of the oxygen required for the complete combustion is 0.091 gm.
Mass is the quantity or the weight of the substance occupied in the reaction and is the product of the molar mass and the moles of the substance.
The reaction for the combustion of propane can be shown as:
[tex]\rm C_{3}H_{8} + 5O_{2} \rightarrow 3CO_{2} + 4H_{2}O[/tex]
Moles of propane can be calculated as:
[tex]\begin{aligned}\rm moles &=\rm \dfrac{mass}{molar\; mass}\\\\&= \dfrac{0.025}{44.1}\\\\&= 5.66\times 10^{-4}\end{aligned}[/tex]
The ratio of the number of moles of propane and oxygen is 1:5. So the moles of oxygen will be [tex]2.83 \times 10^{-3}\;\rm mol[/tex].
Mass of oxygen can be calculated as:
[tex]\begin{aligned}\rm mass &= \rm molar\;mass \times mass\\\\&= 2.83 \times 10^{-3}\;\rm mol \times 32 \;\rm g/mol\\\\&= 0.091\;\rm gm\end{aligned}[/tex]
Therefore, option D. 0.091 gm is the mass of oxygen.
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