contestada

5.00 kg glycol, Ca(OH)2. [this is antifreezel] is added to your radiator. If your radiator contains 12.0 kg
of water, what would be the freezing point of the water-antifreeze mixture? The molal freezing point
depression constant for water is 1.86 'C.kg/mole.

Respuesta :

okpalawalter8

The freezing point is mathematically given as

ft=-12.5C

What would be the freezing point ?

Question Parameters:

5.00 kg glycol, Ca(OH)2. [this is antifreeze] is added to your radiator. If your radiator contains 12.0 kg

The molar freezing point depression constant for water is 1.86 'C.kg/mole.

Generally the equation for the Freezing point  is mathematically given as

ft=k  f [tex]\frac{wB}{Mb}*1000/Wa[/tex]

Therefore

0-ft=1.89*5000.62*1/12

ft=-12.5C

For more information on Temperature

https://brainly.com/question/13439286

Otras preguntas