The solution the equation [tex]\rm log(2t+4)=log(14-3t)[/tex] is t = 2.
Considering that the logarithm function is injective then the log is removing from the both sides and solving the equation for the value of t.
Given
The equation is;
[tex]\rm log(2t+4)=log(14-3t)[/tex]
The solution of the equation is;
[tex]\rm log(2t+4)=log(14-3t)\\\\2t+4=14-3t\\\\2t+3t=14-4\\\\5t=10\\\\t=\dfrac{10}{5}\\\\t=2[/tex]
Hence, the solution the equation [tex]\rm log(2t+4)=log(14-3t)[/tex] [tex]\rm log(2t+4)=log(14-3t)[/tex] is t = 2.
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