Answer:
54
Step-by-step explanation:
We are given the sequence or function:—
[tex]\displaystyle \large{a(n) = 3(2)^n}[/tex]
To find the sum of 1st term and 4th term, first we must find the first term and the fourth term which can be done by substituting n = 1 and n = 4.
[tex]\displaystyle \large{a(1)=3(2)^1}\\\displaystyle \large{a(1)=3 \cdot 2}\\\displaystyle \large{a(1)=6}[/tex]
Then when n = 4.
[tex]\displaystyle \large{a(4) = 3(2)^4}\\\displaystyle \large{a(4) = 3 \cdot 16}\\\displaystyle \large{a(4) = 48}[/tex]
Therefore, the sum of 1st term and 4th term is:—
[tex]\displaystyle \large{a(1)+a(4) = 6+48}\\\displaystyle \large{a(1)+a(4)=54}[/tex]
