An object is 3.0 cm from a concave mirror, with a focal length of 1.5 cm. Calculate the image distance. Remember to include your data, equation, and work when solving this problem. A concave mirror is shown with curvature positioned at 8 on a ruler that goes from 0 to 14 centimeters. The object is located at 5, and the focal point is located at 6.5.

Respuesta :

This question involves the concepts of focal length and mirror formula.

The image distance will be "1 cm".

MIRROR FORMULA

The mirror formula relates the focal length, image distance, and object distance through the following formula:

[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{q}[/tex]

where,

  • f = focal length =1.5 cm
  • p = object distance = 3 cm
  • q = image disance = ?

Therefore.

[tex]\frac{1}{1.5\ cm}=\frac{1}{3\ cm}+\frac{1}{q}\\\\\frac{1}{1.5\ cm}-\frac{1}{3\ cm}=\frac{1}{q}\\\\0.667 + 0.333 = \frac{1}{q}\\\\[/tex]

q = 1 cm

Learn more about mirror formula here:

https://brainly.com/question/3459308

Answer:

The image distance is 3.0 cm

Explanation:

Object distance: 3.0 cm          Focal length: 1.5 cm       Image distance: ? cm

1/f=(1/ do)+(1/di​​​​​​​)

1/1.5=(1/3.0)+(1/x)

(2/3)-(1/3)=1/x

1/3=1/x

x=3.0 cm

The image distance is 3.0 cm.