The zeros of the quadratic function f(x) = 2x² + 8x – 3 is x = -2 - √11/4 and x = -2 + √11/4
A quadratic function is in the form:
y = ax² + bx + c
Given that:
f(x) = 2x² + 8x - 3, hence:
The zero is at:
2x² + 8x - 3 = 0
2x² + 8x = 3
Dividing through by 2:
x² + 4x = 3/2
add to both sides 4:
(x + 2)² = 3/2 + 4
(x + 2)² = 11/4
x + 2 = ±√11/4
x = -2 ±√11/4
The zeros of the quadratic function f(x) = 2x² + 8x – 3 is x = -2 - √11/4 and x = -2 + √11/4
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