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2. A gas that occupies a volume of 6.75 L at 89.0 atm will occupy what volume at 68.55 mm Hg if the temperature remains constant?

Respuesta :

First convert pressure to atm

  • 1atm=760mm hg
  • 68.55 mm Hg= 0.09atm

Now

  • V1=6.75L
  • V2=?
  • P1=89atm
  • P2=0.09atm

Apply Boyle's law

[tex]\\ \rm\Rrightarrow P1V1=P2V2[/tex]

[tex]\\ \rm\Rrightarrow 89(6.75)=0.09V2[/tex]

[tex]\\ \rm\Rrightarrow 600.75=0.09V2[/tex]

[tex]\\ \rm\Rrightarrow V2=\dfrac{600.75}{0.09}[/tex]

[tex]\\ \rm\Rrightarrow V2=6675L[/tex]

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