Respuesta :

Given :

  • Length of the plank = 300 cm.
  • Breadth of the plank = 30 cm.

⠀

To Find :

  • The perimeter and area of the plank.

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Solution :

Perimeter of the plank :

[tex]\: {\qquad \dashrightarrow \sf 2 \times (Length + Breadth) }[/tex]

[tex]\: {\qquad \dashrightarrow \sf{{ 2 \times (300 + 30) \: cm }}}[/tex]

[tex]\: {\qquad \dashrightarrow \sf{{ 2 \times (330) \: cm }}}[/tex]

[tex]\: {\qquad \dashrightarrow \sf{{ 600 \: cm }}}[/tex]

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Area of the plank :

[tex]\: {\qquad \dashrightarrow \sf (Length \times Breadth) }[/tex]

[tex]\: {\qquad \dashrightarrow \sf (330 \times 30) \: {cm}^{2} }[/tex]

[tex]\: {\qquad \dashrightarrow \sf 9 000 \: {cm}^{2} }[/tex]

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SupremeStrange

Step-by-step explanation:

Given :-

  • Length = 300cm
  • Width = 30 cm

To find :-

  • Perimeter and area of plank

Solution :-

Perimeter of rectangular plank = 2(L+W)

putting the values,

perimeter = 2(300+30)cm

⇝660 cm

Area of rectangular plank = L × W

putting the known values ,

Area = 300 × 30 cm²

⇝ 9000cm²

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