Consider the line y=-9x+5.
Find the equation of the line that is parallel to this line and passes through the point (7, 2).
Find the equation of the line that is perpendicular to this line and passes through the point (7, 2).

Respuesta :

Step-by-step explanation:

1) if the point A(7;2) and the given line is in slope-interception form, then the  required parallel line has the same slope, its equation can be written as: y=-9x+C, where C - unknown number;

2) to calculate the C it is needed to substitute the A(7;2) into the required equation of the parallel line:

2=-9*7+C; ⇒ C=65.

3) the parallel line is: y=-9x+65.

4) if the point A(7;2) and the given line is in slope-interception form, then the slope of the perpendicular line is: (-1)/(-9)=1/9, and the required equation of the perpendicular line can be written as:

y=1/9 *x+C, where C - unknown number;

5) to calculate the C it is enough to substitute the A(7;2) into the required equation of the parallel line:

2=1/9 *7+C; ⇒ C=11/9;

6) the perpendicular line is:

[tex]y=\frac{1}{9} x+\frac{11}{9}.[/tex]