1. since A^2= 36x^2, a=?
2. since b^2= 49, b=?

Answer:
D
Step-by-step explanation:
36x² - 49 ← is a difference of squares and factors in general as
a² - b² = (a - b)(a + b)
then
36x² - 49
= (6x)² - 7²
= (6x - 7)(6x + 7)
Thus 6x - 7 is a factor of the expression
We need to simplify the expression 36x² - 49 , but let's recall the identity which is the main key to solve this question i.e
So , here we can write the above expression as
[tex]{:\implies \quad \sf (6x)^{2}-(7)^{2}}[/tex]
Now , using the above identity this can be written as :
[tex]{:\implies \quad \sf (6x-7)(6x+7)}[/tex]
So , here both (6x-7) and (6x+7) are factors of 36x²- 49 , but in the options their is only 6x - 7.
Hence , Option D) 6x - 7 is correct
As here , 36x² = (6x)² = a² , so a = 6x and as 49² = 7² = b² , so b = 7