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If a 3 kg block rests on a rough horizontal table and experienced a 2 N force of static friction then what is the coefficient of static friction between the block and the table

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asuwafohjames

The coefficient of static friction of the block is 0.068.

What is static friction?

This is the force between two bodies in contact and tends to oppose their motion. It is also the force that keeps two bodies at rest

To calculate the coefficient of static friction, we use the formula below.

Formula:

  • F = mgμ............. Equation 1

Where:

  • F = Horizontal force
  • m = mass of the block
  • g = acceleration due to gravity
  • μ = coefficient of static friction.

Make μ the subject of the equation

  • μ = F/mg.............. Equation 2

From the question,

Given:

  • m = 3 kg
  • g = 9.8 m/s²
  • F = 2 N

Substitute these values into equation 2

  • μ = 2/(3×9.8)
  • μ = 2/29.4
  • μ = 0.068.

Hence, The coefficient of static friction of the block is 0.068.

Learn more about static friction here: https://brainly.com/question/13680415

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