5. For the data in the table below, find the sum of the absolute deviations for the predicted values
given by the median-median line, y = 3.6x-0.4.

5 For the data in the table below find the sum of the absolute deviations for the predicted values given by the medianmedian line y 36x04 class=

Respuesta :

Based on the absolute deviations and the predicted values, the sum of absolute deviations will be 4.8.

What would be the sum of absolute deviations from predicted values?

This can be found as:

= ∑ (Observed value - Predicted value)

The observed values are given in the table and the predicted values will be calculated using y = 3.6x - 0.4.

Solving gives:

=  [3 - (3.6 x 1 - 0.4)] + [7 - (3.6 x 2 - 0.4)] + [ 9 - (3.6 x 3 - 0.4)] + [14 - (3.6 x 4 - 0.4)] + [15 - (3.6 x 5 - 0.4)] + [21 - (3.6 x 6 - 0.4)] + [25 - (3.6 x 7 - 0.4)]

= 0.2 + 0.2 + 1.4 + 0 + 2.6 + 0.2 + 0.2

= 4.8

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