Answer:
Step-by-step explanation:
A function is even if [tex]f(x)=f(-x)[/tex], or if the graph has a rotational symmetry about the x-axis. A function is odd if [tex]f(x)=-f(-x)[/tex]. For example, if you were to reflect that graph about the y-axis. Would it present symmetry?
From the graph we know from the fundamental theorem of Algebra that since f has 3 distinct roots, and changes directions three times, we are dealing with a cubic equation in the form of [tex]f(x)=x(x+2)(x-2)[/tex]
Since the equation is known, try the formulas
First, test for an even function, [tex]f(x)=f(-x)[/tex], this means that for our function, f, [tex]f(2)=f(-2)[/tex] see if this holds true
[tex]2(2+2)(2-2) = -2(-2+2)(-2-2)\\2(4)(0)=-2(0)(-4)\\0 = 0[/tex]
This means that the function is even.
