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Question 6 (2 points) If 100.0 mL ethyl alcohol weighs 78.5 g, determine the volume in litres occupied by 1.59 kg of ethyl alcohol. Answer Instructions:​

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The volume in litres occupied by 1.59 Kg of ethyl alcohol given the data from the question is 2.03 L

How to determine the mole of 78.5 g of ethyl alcohol

  • Mass of ethyl alcohol = 78.5 g
  • Molar mass of ethyl alcohol = 46.07 g/mol
  • Mole of ethyl alcohol =?

Mole = mass / molar mass

Mole of ethyl alcohol = 78.5 / 46.07

Mole of ethyl alcohol = 1.7 mole

How to determine the mole of 1.59 Kg of ethyl alcohol

  • Mass of ethyl alcohol = 1.59 Kg = 1.59 × 1000 = 1590 g
  • Molar mass of ethyl alcohol = 46.07 g/mol
  • Mole of ethyl alcohol =?

Mole = mass / molar mass

Mole of ethyl alcohol = 1590 / 46.07

Mole of ethyl alcohol = 34.5 moles

How to determine the new volume

  • Initial volume (V₁) = 100 mL = 100 / 1000 = 0.1 L
  • Initial mole (n₁) = 1.7
  • New mole (n₂) = 34.5 moles
  • New Volume (V₂) =.?

V₁ / n₁ = V₂ / n₂

0.1 / 1.7 = V₂ / 34.5

Cross multiply

1.7 × V₂ = 0.1 × 34.5

Divide both side by 1.7

V₂ = (0.1 × 34.5) / 1.7

V₂ = 2.03 L

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