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Consider the line y=9x-1.
Find the equation of the line that is perpendicular to this line and passes through the polnt (6, -5).
Find the equation of the line that is parallel to this line and passes through the point (6,-5).

Respuesta :

Step-by-step explanation:

Slope=9

i)

[tex]y−y1=m(x−x1)[/tex]

When line is parallel

y+5=9(x-6)

y+5 = 9x - 54

59 = 9x-y

When line is perpendicular

y+5=-1/9(x-6)

9(y+5)= -1(x-6)

9y + 45 = -x+6

x+9y = -39

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