The spring stretch by 80cm if a spring constant 0.5 m has a force of 40 newtons applied to it
According to Hookes law
F = ke
where
F is the applied force = 40N
k is the spring constant
e is the extension = 0.5
Substitute
40 = 0.5e
e = 40/0.5
e = 80cm
Hence the spring stretch by 80cm if a spring constant 0.5 m has a force of 40 newtons applied to it
Learn more on hookes law here: https://brainly.com/question/12253978
