The [OH] of vinegar to the nearest hundredth is 2.82 * 10^-5
How to calculate the [OH] of a substance:
The sum of the pH and pOH of a substance is 14. Mathematically
[OH−] = Antilog (pOH)
Given the following parameters
[OH−] = Antilog (9.45)
Substitute
[OH−] = 2.82 * 10^-5
Hence the [OH] of vinegar to the nearest hundredth is 2.82 * 10^-5
Learn more on pH and pOH here:https://brainly.com/question/13557815
