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You push a 25.0kg wooden box across a wooden floor at a constant speed of 1.0m/s . the coefficient of kinetic friction is 0.20 . how large is the force that you exert on the box?

Respuesta :

okpalawalter8

For  a 25.0kg wooden box across a wooden floor at a constant speed of 1.0m/s, The force is mathematically given as

F=49N

What is the force that you exert on the box?

Generally, the equation for the Force   is mathematically given as

F=uN

Therefore

F=25*9.8*0.20

F=49N

In conclusion, the force is

F=49N

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