For the solubility of a gas is 0.890 g/L at a pressure of 120 kPa, the solubility of the gas, if the pressure is changed to 100 kPa is mathematically given as
c=0.741g/l
Generally, the equation for the Pressure is mathematically given as
p=kc
Therefore
k=p/c
k = 120 /0.890
k=134.8
In conclusion, if p=100kpa
c=p/k
c=100/134.8
c=0.741g/l
Read more about mass
https://brainly.com/question/15959704