The value of the given function is as follows sin a = 3/5, cos a =4/5 and sec a = 5/4.
How do we find the sin, tan, and sec function?
By right-angled triangle, we can find the trigonometric function from the sides of the triangle.
sin x = perpendicular/ hypotenuse
cos x = base/ hypotenuse
sec x = hypotenuse /base
From a triangle ABC of base 4, perpendicular 3, and hypotenuse 5, we get
sin a = perpendicular/ hypotenuse
= 3/5
cos a = base/ hypotenuse
= 4/5
sec a = hypotenuse /base
= 5/4
Hence, the value of the given function is as follows sin a = 3/5, cos a =4/5 and sec a = 5/4.
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