Using an arithmetic sequence, it is found that the clock chimes 132 times in a 24-h period.
In an arithmetic sequence, the difference between consecutive terms is always the same, called common difference d.
The nth term of an arithmetic sequence is given by:
[tex]a_n = a_1 + (n - 1)d[/tex]
In which [tex]a_1[/tex] is the first term.
The sum of the first n terms is given by:
[tex]S_n = \frac{n(a_1 + a_n)}{2}[/tex]
In this problem, as the day is divided in two 12-hours period, the total will be twice the sum of the 12 elements of the following sequence:
{0, 1, 2, 3, ..., 11}
In which [tex]a_1 = 0, a_11 = 11, n = 12[/tex].
Then:
[tex]T = 2\frac{12(0 + 11)}{2} = 12 \times 11 = 132[/tex]
The clock chimes 132 times in a 24-h period.
More can be learned about arithmetic sequences at https://brainly.com/question/6561461