contestada

Jan'ai was asked to determine the minimum for a function with zeros located at –1 and 5, which also has a y-intercept of (0, –25). her work is shown. which best describes the first error in jan'ai's work? she incorrectly determined the factors for the beginning function. she incorrectly determined the a value. she incorrectly transformed the equation to standard form. she incorrectly determined the x-coordinate of the vertex.

Respuesta :

The first error in Jan'ai's work in determining the considered function is given by: Option D: She incorrectly determined the x-coordinate of the vertex.

What are the coordinates of vertex for a quadratic function?

For a quadratic function of the form [tex]y = ax^2 + bx + c[/tex], its vertex form is obtained as:

[tex]y = ax^2 + bx + c\\y =a(x^2 + bx/a) + c\\y = a(x^2 + 2(b/2a)x + (b/2a)^2 -(b/2a)^2 )+ c\\y = a(x^2 + 2(b/2a)x + (b/2a)^2) -a \times (b/2a)^2 + c\\\\y = a(x+b/2a)^2 - a \times (b/2a)^2 + c[/tex]

For the form [tex]y = a(x-h)^2 + k[/tex], the vertex has coordinates (h, k)

Thus, for the obtained equation [tex]y = a(x+b/2a)^2 - a \times (b/2a)^2 + c[/tex], we get the coordinates of vertex as:

[tex]h = -b/2a[/tex], [tex]k = c - a\times(b/2a)^2[/tex]

Thus, the coordinates of vertex of  [tex]y = ax^2 + bx + c[/tex] is:

[tex](h,k) = (-b/2a, c - a \times (b/2a)^2 )[/tex]

The missing steps of work of Jan'ai are:

  1. Begin to write a function in factored form. [tex]f(x) = a(x+1)(x-5)[/tex]
  2. Substitute x = 0, y = f(x) =  -25 to determine a. [tex]-25 = a(0+1)(0-5)[/tex]
  3. Simplify and solve to find a. [tex]a=5[/tex]
  4. Rewrite the function. [tex]f(x) = 5(x+1)(x-5)[/tex]
  5. Rewrite in standard form. [tex]f(x) = 5x^2-20x-25[/tex]
  6. Find the x-coordinate of the vertex. [tex]x = -20/2(5) = -20/10; x = -2[/tex]
  7. Find the y-coordinate of the vertex.

[tex]y = 5x^2-20x-25[/tex]

[tex]y = 5(-2)^2-20(-2)-25[/tex]

[tex]y = 35[/tex]

so (-2,35) is the coordinate of the vertex, which denotes the minimum.

So, as we see, in the 5th step, Jan'ai had the quadratic function [tex]f(x) = 5x^2-20x-25[/tex],

Comparing this to [tex]f(x) = ax^2 + bx + c[/tex], we get a = 5, b = -20, c = -25

The vertex's x-coordinate will be on -b/2a = -(-20)/ 2(5) = 20/10 = 2

But Jan'ai didn't putted that negative sign before b. in the 6th step.

Thus, the first error in Jan'ai's work in determining the considered function is given by: Option D: She incorrectly determined the x-coordinate of the vertex.

Learn more about the vertex form of a quadratic equation here:

https://brainly.com/question/9912128

Answer:

The answer is D on edge

Step-by-step explanation:

Otras preguntas