Considering a six-sided spinner, it is found that the probability of spinning a 1 and tossing a head is of [tex]\frac{1}{12}[/tex].
A probability is given by the number of desired outcomes divided by the number of total outcomes.
In this problem:
Since the events are independent, the probability of spinning a 1 and tossing a head is given by:
[tex]p = \frac{1}{6} \times \frac{1}{2} = \frac{1}{12}[/tex].
More can be learned about probabilities at https://brainly.com/question/14398287
