Respuesta :

#b

[tex]\\ \rm\rightarrowtail tan47=\dfrac{b}{21}[/tex]

[tex]\\ \rm\rightarrowtail b=21tan47[/tex]

[tex]\\ \rm\rightarrowtail b=22.5[/tex]

#c

[tex]\\ \rm\rightarrowtail cos47=\dfrac{21}{c}[/tex]

[tex]\\ \rm\rightarrowtail c=21/cos47[/tex]

[tex]\\ \rm\rightarrowtail c=30.88[/tex]

semsee45

Answer:

c = 30.8 (nearest tenth)

Step-by-step explanation:

Pythagoras' Theorem: a² + b² = c²

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

Given:

  • a = 21
  • b = 22.5

Substitute given values into the formula and solve for c:

⇒ 21² + 22.5² = c²

⇒ 947.25 = c²

⇒ c = ±√(947.25)

⇒ c = ±30.8 (nearest tenth)

As distance is positive, c = 30.8 (nearest tenth) only

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