Hello There!!
Solution For Given Question
Three times x is 13 less than y
[tex]3x = y - 13 \\ = > 3x + 13 = y[/tex]
The sum of x and two times y is 12.
[tex]x + 2y = 12[/tex]
Replacing Value of Y with 3x + 13
[tex]x + 2y = 12 \\ \\ \implies x + 2(3x + 13) = 12 \\ \\ \implies x + 6x + 26 = 12 \\ \\ \implies7x = 12 - 26 \\ \\ \implies 7x = - 14 \\ \\ \implies x = \cancel\frac{ - 14}{7} \\ \\ \implies x = - 2[/tex]
Now we need to fine Value of'y' i e.,
[tex]y = 3x + 13 \\ \\ \implies y = 3( - 2) + 13 \\ \\ \implies y = - 6 + 13 \\ \\ \implies y = 7[/tex]
[tex] \therefore \text{option c.(y = 7) is your answer}[/tex]
Hope this helps
