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Answer:

So, we can check step by step.

2x^2-7x+5=0

So, 2x^2-2x-5x+5=0 is correct

2x(x-1)=2x^2-2x, 5(x-1)=-5x + 5= 0, that step is correct

(I'll skip the next step)

2x-5=0,

2x=5

x=5/2, NOT 2/5

The other one is correct

Sorry if this seems a bit vague!

[tex]\\ \rm\Rrightarrow 2x^2-7x+5=0[/tex]

  • Split the middle term

[tex]\\ \rm\Rrightarrow 2x^2-2x-5x+5=0[/tex]

  • Take common

[tex]\\ \rm\Rrightarrow 2x(x-1)-5(x-1)=0[/tex]

  • Factor up

[tex]\\ \rm\Rrightarrow (2x-5)(x-1)=0[/tex]

  • Find x

[tex]\\ \rm\Rrightarrow x=5/2,1[/tex]

Lauren written 2/5 instead of 5/2

Let's verify once more

  • 2x-5=0
  • 2x=5
  • x=5/2

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