Hemophilia is an X-linked recessive genetic disorder. A baby girl is found to have inherited the trait from her parents. What are the phenotypes of the parents?

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08-04-2022
Biology

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Hemophilia is an X-linked recessive genetic disorder. A baby girl is found to have inherited the trait from her parents. What are the phenotypes of the parents?

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marianaegarciaperedo marianaegarciaperedo · Answer 1 · 2022-04-13T12:00:11+02:00

X-linked genes are inherited. The affected girl's father is hemophilic (X-Y), and the mother might be either hemophilic (X-X-) or carrier normal (X+X-).

What are the X-linked genes?

These are the genes located in the X séx chromosome and not in the somatic ones.

Traits coded by these genes are inherited. This is, X-linked genes are transmitted from parents to children through generations.

According to this, X-linked genetic disorder will be inherited as well.

Men have a high probability of being affected since they only have one copy of the X chromosome.
In women, the effect of the mutation might be musk in heter0zyg0us state.

Hemophilia is a X-linked recessive genetic disorder.

Let us represent the recessive allele with the symbol -, and the dominant allele with the symbol +.

X- is the chromosome carrying the recessive allele

X+ is the chromosome carrying the dominant allele

For the affection to be expressed, the person must be either,

X-X- ⇒ woman/girl

X-Y ⇒ man/boy

If the baby girl is found to have inherited the trait from her parents, then her genotype is X-X-. She must have received one X- chromosomes from each parent.

Her father provided the X chromosome, so he must be hemophilic (X-Y)

Her mother provided the other X chromosome, but she can be either a carrier (heter0zyg0us, X+X-) or hemophilic (h0m0zyg0us recessive, X-X-).

Options,

Cross 1) affected father x carrier mother

Parentals) X-Y x X+X-

Gametes) X- Y X+ X-

Punnett square) X- Y

X+ X+X- X+Y

X- X-X- X-Y

F1) 1/2 = 50% of the progeny is expected to be healthy (25% X+X- girls + 25% X+Y boys)

1/2 = 50% of the progeny is expected to be hemophilic (25% X-X- girls + 25% X-Y boys)

Cross 2) affected father x affected mother

Parentals) X-Y x X-X-

Gametes) X- Y X- X-

Punnett square) X- Y

X- X-X- X-Y

F1) 100% of the progeny is expected to be hemophilic (50% X-X- girls + 50% X-Y boys)

the phenotype of the father ⇒ hemophilic (X-Y)
the phenotype of the mother ⇒ normal carrier (X+X-) or hemophilic (X-X-)

You can learn more about séx-linked genes at

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