The length of the diameter, in meters, of the circular area that gets watered by the sprinkler for this condition is given by: Option B: 8 m
If a circle O has radius of r units length and that it has got its center positioned at (h, k) point of the coordinate plane, then, its equation is given as:
[tex](x-h)^2 + (y-k)^2 = r^2[/tex]
For this case, the equation of the circle that models tha circular area considered is:
[tex](x-9)^2 + (y+11)^2=16[/tex]
Writing this in standard form and comparing it with the standard equation, we get:
[tex](x-9)^2 + (y+11)^2=16\\(x-9)^2 + (y - (-11) )^2 = 4^2[/tex] (didn't took (-4)² = 16 since radius cannot be negative).
Thus, we get center's coordinate as (9,-11) and radius of 4
The diameter of that circular area = twice of radius of the circle which models it = 2 × 4 = 8 meters.
Thus, the length of the diameter, in meters, of the circular area that gets watered by the sprinkler for this condition is given by: Option B: 8 m
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